The following data are from a simple random sample (The population is infinite):
Sample Size: 166
Sample Mean: 15.5
Population Variance: 138
If the Analysis was run as a two tailed test find the Margin of error ± using an alpha value =0.10 (Input the absolute value for the margin of error (that is if the answer is ± 3.1, input 3.1) , Use 2 decimals in your answer) Use the appropriate table.
Given:
Sample Size = n = 166
Sample Mean = = 15.5
Population Variance, 2 = 138
Standard deviation, = √138 = 11.7473
Significance level, = 0.10
At 0.10 significance level, the critical value of z is
Z/2 = Z0.10/2 = 1.645......(from z table)
Margin of error, E = Z/2 × /√n
= 1.645 × 11.7473/√166
= 1.645 × 0.9118
= 1.50
Therefore margin of error is 1.50 (try 1.49 if getting wrong)
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