Question

Flip 2 fair coins. Then the sample space is {HH, HT, TH, TT} where T = tails and H = heads. The outcomes HT & TH are different & the HT means that the first coin showed heads and the second coin showed tails. The TH means that the first coin showed tails and the second coin showed heads. Let A = the event of getting at most one tail. What is the probability of event A?

Answer 1

The sample space is {HH, HT, TH, TT}

so, each of the sample point occur with probability 1/4.

Let A be the event of getting at most one tail. We have to find probability of A.

P(A) = P(at most one tail) = P(no tails) + P(only one tail)

                                       = P(HH) + P(HT, TH)

                                      

Probability of getting at most one tail is 0.75.         (Answer)