32)
A researcher is studying the heights of men with a certain medical condition. She collects a sample of 33 such men and finds the mean height of the sample to be x̄ = 65.1 inches. Assume that the standard deviation of heights of men with the condition is the same as that of the general population, σ = 2.8 inches.
a) Find a 99% confidence interval for the true mean height of the population of mean with this condition.
b) Provide the right endpoint of the interval as your answer.
Round your answer to 2 decimal places.
Please explain each step (even if you are using a ti-84 calculator) in detail. Thank you!
a)
significance level = 1 - 0.99 = 0.01
From Z table,
Critical value Z/2 = 2.576
99% confidence interval for is
- Z/2 * / sqrt(n) < < + Z/2 * / sqrt(n)
65.1 - 2.576 * 2.8 / sqrt ( 33) < < 65.1 + 2.576 * 2.8 / sqrt ( 33)
63.84 < < 66.36
99% CI is ( 63.84 , 66.36 )
b)
Right endpoint = 66.36
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