Assume that the readings at freezing on a batch of thermometers are normally distributed with a mean of 0°C and a standard deviation of 1.00°C. A single thermometer is randomly selected and tested. Find P59, the 59-percentile. Round to 3 decimal places. This is the temperature reading separating the bottom 59% from the top 41%.
P59 = °C
Solution: 59-percentile is 0.228°C
Given information,
Assume that the readings at freezing on a batch of thermometers are normally distributed with a mean of 0°C and a standard deviation of 1.00°C.
We need to find a score x so that the corresponding cumulative normal probability is equal to 0.59. Mathematically, x is such that:
P(X<=x)=0.59
The corresponding z score score so that the cumulative standard normal probability distribution is 0.59 is Zc=0.2275
x= μ+zc×σ =0+0.2275×1=0.2275
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