A quality control expert at LIFE batteries wants to test their new batteries. The design engineer claims they have a variance of 2601 with a mean life of 1191 minutes. If the claim is true, in a sample of 167 batteries, what is the probability that the mean battery life would differ from the population mean by more than 3.5 minutes? Round your answer to four decimal places.
Solution :
= / n = 51/ 167
= 1 - P[ -3.5 / 51/ 167 < ( - ) / < 3.5 / 51/ 167]
= 1 - P(-0.89 < Z < 0.89)
= 0.3735
Probability = 0.3735
Get Answers For Free
Most questions answered within 1 hours.