TABLE 3
YEAR |
1 |
2 |
3 |
4 |
5 |
6 |
7 |
8 |
9 |
10 |
NO.OF(‘000) |
20 |
25 |
28 |
32 |
40 |
45 |
48 |
52 |
56 |
60 |
(i). Compute the Trend Projection equation expressing the number of credit card transactions as a function of time.
(ii) Use that equation to predict the number of credit card transactions in each of the next two years.
Year (x) | No.of ('000)(y) | x^2 | xy | |
1 | 20 | 1 | 20 | |
2 | 25 | 4 | 50 | |
3 | 28 | 9 | 84 | |
4 | 32 | 16 | 128 | |
5 | 40 | 25 | 200 | |
6 | 45 | 36 | 270 | |
7 | 48 | 49 | 336 | |
8 | 52 | 64 | 416 | |
9 | 56 | 81 | 504 | |
10 | 60 | 100 | 600 | |
Sum | 55 | 406 | 385 | 2608 |
here to find trend equation, we require the above table
here if the equation is
y^ = a + bt
a = [(Σy) (Σx2 ) - (Σx) (Σxy)]/ [ n (Σx2 ) - (Σx)2 ]
a = [(406 * 385 - 55 * 2608)]/ [10 * 385 - 55 * 55]
a = 15.6
b = [ n(Σxy) - (Σx)((Σy)]/ [ n (Σx2 ) - (Σx)2 ]
b = [10 * 2608 - 55 * 406]/[10 * 385 - 55 * 55]
b = 4.5454
y^ = 15.6 + 4.5454 t
(b) So here forecast equation is y^ = 15.6 + 4.5454 t
y^(11) = 15.6 + 4.5454 * 11 = 65.6
y^(12) = 15.6 + 4.5454 * 12 = 70.145
Get Answers For Free
Most questions answered within 1 hours.