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Question No 3. Tests Using Contingency Tables: A researcher selected sample of customs from 4 companies...

Question No 3. Tests Using Contingency Tables:

A researcher selected sample of customs from 4 companies and asked them if the companies care give warranty on sold items or not. Assume observed values from your own (fill the below table by assuming any values of your choice) and test the claim that the proportion of customers of each company who got warranty is the same for each company by choosing alpha of your own choice. (Marks 2.5)

Company A

Company B

Company C

Company D

Total

Warranty: Yes

55

60

25

30

170

Warranty: No

14

22

18

10

64

Total

69

82

43

40

234

A = 0.03

Step 1: HO = u1 = u2 = u3 = u4

At least 1 mean is different from the others

Step 2: : Find the critical value at = 0.03 with (2-1)(4-1) = 3 degree of freedom

D.f = 5-3 = 2 and a = 0.03. CV =

Homework Answers

Answer #1

The hypothesis being tested is:

H0: The proportion of customers of each company who got a warranty is the same for each company

Ha: The proportion of customers of each company who got a warranty is not the same for each company

observed expected O - E (O - E)² / E
55 42.500 12.500 3.676
60 42.500 17.500 7.206
25 42.500 -17.500 7.206
30 42.500 -12.500 3.676
170 170.000 0.000 21.765
8.947 critical value
21.76 chi-square
3 df
.0001 p-value

The critical value is 8.947.

df = 4 - 1 = 3

The test statistic is 21.76.

The p-value is 0.0001.

Since the p-value (0.0001) is less than the significance level (0.03), we can reject the null hypothesis.

Therefore, we can conclude that the proportion of customers of each company who got a warranty is not the same for each company.

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