Question No 3. Tests Using Contingency Tables:
A researcher selected sample of customs from 4 companies and asked them if the companies care give warranty on sold items or not. Assume observed values from your own (fill the below table by assuming any values of your choice) and test the claim that the proportion of customers of each company who got warranty is the same for each company by choosing alpha of your own choice. (Marks 2.5)
Company A |
Company B |
Company C |
Company D |
Total |
|
Warranty: Yes |
55 |
60 |
25 |
30 |
170 |
Warranty: No |
14 |
22 |
18 |
10 |
64 |
Total |
69 |
82 |
43 |
40 |
234 |
A = 0.03
Step 1: HO = u1 = u2 = u3 = u4
At least 1 mean is different from the others
Step 2: : Find the critical value at = 0.03 with (2-1)(4-1) = 3 degree of freedom
D.f = 5-3 = 2 and a = 0.03. CV =
The hypothesis being tested is:
H0: The proportion of customers of each company who got a warranty is the same for each company
Ha: The proportion of customers of each company who got a warranty is not the same for each company
observed | expected | O - E | (O - E)² / E |
55 | 42.500 | 12.500 | 3.676 |
60 | 42.500 | 17.500 | 7.206 |
25 | 42.500 | -17.500 | 7.206 |
30 | 42.500 | -12.500 | 3.676 |
170 | 170.000 | 0.000 | 21.765 |
8.947 | critical value | ||
21.76 | chi-square | ||
3 | df | ||
.0001 | p-value |
The critical value is 8.947.
df = 4 - 1 = 3
The test statistic is 21.76.
The p-value is 0.0001.
Since the p-value (0.0001) is less than the significance level (0.03), we can reject the null hypothesis.
Therefore, we can conclude that the proportion of customers of each company who got a warranty is not the same for each company.
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