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In survey of 952 respondents, 620 of them voted in a recent electionFind a 95% confidence...

In survey of 952 respondents, 620 of them voted in a recent electionFind a 95% confidence interval estimate for the true population proportion that voted in this election
Math   Statistics-And-Probability   
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Answer #1

Solution :

Given that,

Point estimate = sample proportion = = x / n = 620 / 952 = 0.651

1 - = 1 - 0.651 = 0.349

Z/2 = 1.96

Margin of error = E = Z / 2 * (( * (1 - )) / n)

= 1.96 * (((0.651 * 0.349) / 952)

Margin of error = E = 0.030

A 95% confidence interval for population proportion p is ,

- E < p < + E

0.651 - 0.030 < p < 0.651 + 0.030

0.621 < p < 0.681

The 95% confidence interval for the population proportion p is : 0.621 , 0.681

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