a) The expected percentage of the sample that we expect out of
them who will favor the bond is given as: p = 0.6
Therefore 60% is the expected percentage of the sample that
would favor the bond.
b) np = 200*0.6 = 120 > 5 and n(1-p) = 200*0.4 = 80 >
5
np(1-p) = 200*0.6*0.4 = 48 >= 10
Therefore the Central limit theorem assumptions are applicable here.
c) the standard error for sample proportion is computed here as:
Therefore 0.0346 is the required standard error for the sample proportion here.
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