WITH 80% CONFIDFENCE, FOR SAMPLE PROPORTION 0.56 AND SAMPLE SIZE 2.2, WHAT THE UPPER CONFIDENCE LIMIT WITH 2 DECIMAL PLACE? _________
Solution:
Given that,
n = 2.2
Point estimate = sample proportion
= 0.56
1 - = 0.44
Z = 0.84
Margin of error = E = Z *(( *(1 - ))/ n
= 0.84 * ((0.56 *0.44)/ 2.2)
= 0.18
Upper confidence limit = + E
= 0.56 +0.81 = 1.37
Note: Please comment below if you have any doubts
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