Question

A researcher studied how two diets compare in terms of weight loss after 6 months.      ...

A researcher studied how two diets compare in terms of weight loss after 6 months.

      40 people used the first diet. Their sample mean was 44, and their sample standard deviation was 10.

       60 people used the first diet. Their sample mean was 37, and their sample standard deviation was 15.

      Give the 92% confidence interval for the true difference between the mean weight losses.

Can we conclude that the two diets really differ in terms of the mean weight loss? Yes/No, because the P value is less than ?

Homework Answers

Answer #1

Confidence interval :-

DF = 97

t(α/2, DF) = t(0.02 /2, 9 ) = 2.821

92% confidence interval is ( 2.577 , 11.423 )

Yes/No, because the P value is less than ?

Test Statistic :-

t = 2.80

P value = 0.0062

Reject null hypothesis if P value < α = 0.02 level of significance
P - value = 0.0062 < 0.08, hence we reject null hypothesis
Conclusion :- Reject null hypothesis

Yes, because the P value is less than α = 0.08

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