Jake has a bag of marbles with 3 blue marbles, 1 white marbles,
and 6 red marbles.
Find the following probabilities of Jake drawing the given marbles
from the bag if the first marble(s) is(are) not returned to the bag
after they are drawn.
a) A Blue, then a red =
b) A red, then a white =
c) A Blue, then a Blue, then a Blue =
Total marbles = 3 + 1 + 6 = 10
a) P(a blue, then a red) =
Hence, 1/5 or 0.2 is the probability of getting A blue then a red.
b) P(red, then a white) =
Hence, 1/15 is the probability of getting A red, then a white.
c) P(blue, then blue, then blue) =
Hence 1/120 is the probability of getting a, blue, then a blue then a blue.
As we are not returning the selected ball that's why denominator is reducing by 1 in all these parts.
Please comment if any doubt. Thank you.
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