You wish to test the following claim (HaHa) at a significance
level of α=0.01α=0.01.
Ho:μ=84.1Ho:μ=84.1
Ha:μ<84.1Ha:μ<84.1
You believe the population is normally distributed, but you do not
know the standard deviation. You obtain a sample of size n=28n=28
with mean M=72.7M=72.7 and a standard deviation of
SD=20.8SD=20.8.
What is the p-value for this sample? (Report answer accurate to
four decimal places.)
p-value =
The p-value is...
This p-value leads to a decision to...
As such, the final conclusion is that...
Im so confused, how do I solve this?
Solution:
Here, we have to use one sample t test for the population mean.
Ho: μ = 84.1
Ha: μ < 84.1
This is a lower tailed test.
We are given
Level of significance = α = 0.01
Sample size = n = 28
Sample mean = Xbar = 72.7
Sample standard deviation = S = 20.8
Degrees of freedom = df = n – 1 = 28 – 1 = 27
Critical t value = -2.4727
(by using t-table)
Test statistic formula is given as below:
t = (Xbar - µ)/[S/sqrt(n)]
t = (72.7 – 84.1)/[20.8/sqrt(28)]
t = -2.9002
P-value = 0.0037
(by using t-table)
The p-value is 0.0037.
The P-value is less than α = 0.01
So, we reject the null hypothesis
This p-value leads to a decision to reject the null hypothesis.
As such, the final conclusion is that there is not sufficient evidence to warrant rejection of the claim that the population mean is less than 84.1.
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