Suppose that you are testing the following hypotheses where the variance is unknown: H0 : µ = 100 H0 : µ ≠ 100 The sample size is n 20. Find bounds on the P-value for the following values of the test statistic. a. t0 = 2.75 b. t0 = 1.86 c. t0 = -2.05 d. t0 = -1.86
Solution
The null and alternative hypothesis is ,
H0 : = 100
Ha : 100
n = 20
degrees of freedom = n - 1 = 20 - 1 = 19
This is the two tailed test .
a) t0 = 2.75
P(t > 2.75) = 1-P (t < 2.75) = 1 - 0.9936 = 0.0064
P-value = 2 * P(t > 2.75)
P-value = 2 * 0.0064
P-value = 0.0128
b) t0 = 1.86
P(t > 1.86) = 1-P (t < 1.86) = 1 - 0.9608 = 0.0392
P-value = 2 * P(t > 1.86)
P-value = 2 * 0.0392
P-value = 0.0784
c) t0 = -2.05
P(t < -2.05) = 0.0272
P-value = 2 * P(t < -2.05)
P-value = 2 * 0.0272
P-value = 0.0544
d) t0 = -1.86
P(t < -1.86) = 0.0392
P-value = 2 * P(t < -1.86)
P-value = 2 * 0.0392
P-value = 0.0784
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