The table below represents the number of hospitalizations for heart attack for men and women in various age groups.
Age | Male | Female |
18-44 | 268 | 93 |
45-64 | 1663 | 686 |
65-84 | 1557 | 1242 |
85 and up | 355 | 578 |
Let A be the event that a patient is female, B be the event that a patient is male, C be the event that a patient is in the age group 45-64, and D be the event that a patient is in the age group 65-84. Answer the following questions:
a.) What is the total sample size? Answer
b.) What is the probability that event B will occur? (round to four decimal places)
P(B) = Answer
c.) What is the probability that event D will occur? (round to four decimal places)
P(D) = Answer
d.) What is the probability that events B and D will occur? (round to four decimal places)
P(B and D) = Answer
e.) Are events B and D mutually exclusive?
no | yes |
f.) What is the probability of either B or D occurring? (round to two decimal places)
P(B or D) = Answer
Age | Male(B) | Female(A) | Total |
18-44 | 268 | 93 | 361 |
45-64(C) | 1663 | 686 | 2349 |
65-84(D) | 1557 | 1242 | 2799 |
85 and up | 355 | 578 | 933 |
Total | 3843 | 2599 | 6442 |
a) Total sample size, n = 6442
b) P(B) = 3843/6442 = 0.5966
c) P(D) = 2799/6442 = 0.4345
d) P(B and D) = 1557/6442 = 0.2417
e) No, the events B and D are not mutually exclusive as the value of P(B and D) is not equal to 0.
f) P(B or D) = P(D) + P(B) - P(B and D)
= 2799/6442 + 3843/6442 - 1557/6442
= 0.7894 = 0.79
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