Question

A consumer advocate group claims the average American household spends more than $874 during Christmas. The...

A consumer advocate group claims the average American household spends more than $874 during Christmas. The claim is tested with a sample of 64 households and finds the average of the sample to be $905 with a standard deviation of $125. Level of significance is 0.05. Answer the following:

a) write Ho and Ha and identify which is the claim

b) identify whether its left, right or two tailed

c) write the p-value

d) decide whether to reject or fail to reject the null hypothesis

e) interpret the final decision in the context of the original claim.

Homework Answers

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
The bag of snack cheese puffs claims the weight of the contents is 11 ounces. The...
The bag of snack cheese puffs claims the weight of the contents is 11 ounces. The quality control officer tests this with a sample of 8 bags of cheese puffs and finds their weights to be the following 11.8, 8.6,  12.6, 7.9, 6.4, 10.4, 13.6, and 9.1 ounces. Test the claim with a level of significance of 0.01 (assume the population is normally distributed) : a) write Ho and Ha and identify which is the claim b) identify whether its left,...
A humane society claims that less than 33​% of U.S. households own a dog. In a...
A humane society claims that less than 33​% of U.S. households own a dog. In a random sample of 404 U.S.​ households, 152 say they own a dog. At a =0.10​, is there enough evidence to support the​ society's claim? ​(a) Write the claim mathematically and identify H0 and Ha. ​(b) Find the critical​ value(s) and identify the rejection​ region(s). (c) Find the standardized test statistic.​ (d) Decide whether to reject or fail to reject the null​ hypothesis, and​ (e)...
A humane society center claims that less than 63% of households in a certain country own...
A humane society center claims that less than 63% of households in a certain country own a pet. In a random sample of 400 households in that country, 236 say that they own a pet. At α=0.0​1, is there enough evidence to support the society's center's claim? Complete parts​ (a) through​ (d) below. (a) Identify the claim and state H0 and Ha. Let p be the population proportion of​ successes, where a success is a household in the country that...
A humane society claims that less than 34​% of U.S. households own a dog. In a...
A humane society claims that less than 34​% of U.S. households own a dog. In a random sample of 399 U.S.​ households, 151 say they own a dog. At alphaequals0.04​, is there enough evidence to support the​ society's claim? ​(a) Write the claim mathematically and identify Upper H 0 and Upper H Subscript a. ​(b) Find the critical​ value(s) and identify the rejection​ region(s). (c) Find the standardized test statistic.​ (d) Decide whether to reject or fail to reject the...
Q1) Last year the government made a claim that the average income of the American people...
Q1) Last year the government made a claim that the average income of the American people was $33,950. However, a sample of 28 people taken recently showed an average income of $34,076 with a standard deviation of $324. Is the government’s estimate too low? Conduct a significance test to see if the true mean is more than the reported average. Use α=0.05. (a) State the null and alternative hypothesis. (b) Calculate the test statistic. (c) Calculate the p-value. Round to...
Q1) Last year the government made a claim that the average income of the American people...
Q1) Last year the government made a claim that the average income of the American people was $33,950. However, a sample of 28 people taken recently showed an average income of $34,076 with a standard deviation of $324. Is the government’s estimate too low? Conduct a significance test to see if the true mean is more than the reported average. Use α=0.05. (a) State the null and alternative hypothesis. (b) Calculate the test statistic. (c) Calculate the p-value. Round to...
A credit card company claims that the mean credit card debt for individuals is greater than...
A credit card company claims that the mean credit card debt for individuals is greater than $4,900. You want to test this claim. You find that a random sample of 38 cardholders has a mean credit card balance of $5,194 and a standard deviation of $550. At α=0.05​, can you support the​ claim? Write the claim mathematically and identify H0 and Ha. Find the critical​ value(s) and identify the rejection​ region(s). Find the standardized test statistic t. Decide whether to...
A sociologist claims that children spent more time watching television in 1981 than children do today....
A sociologist claims that children spent more time watching television in 1981 than children do today. A study was conducted in 1981 to find the time that children watched television on weekdays. Recently, a similar study was conducted. The results of these studies (in hours per weekday) are shown below. Assume the population standard deviation is 0.7 for 1981 and 0.7 for today. At α=0.05, can you support the sociologist's claim? Complete parts (a) through (d) below. 1981 3.2 1.4...
A sociologist claims that children spent more time watching television in 1981 than children do today....
A sociologist claims that children spent more time watching television in 1981 than children do today. A study was conducted in 1981 to find the time that children watched television on weekdays. Recently, a similar study was conducted. The results of these studies (in hours per weekday) are shown below. Assume the population standard deviation is 0.8 for 1981 and 0.6 for today. At α=0.05, can you support the sociologist's claim? Complete parts (a) through (d) below. 1981 1981 2.5...
A diet doctor claims that the average North American is more than 20 pounds overweight. To...
A diet doctor claims that the average North American is more than 20 pounds overweight. To test his claim, a random sample of 20 North Americans was weighed, and the difference between their actual and ideal weights was calculated. The data is listed below: 16 23 18 41 22 18 23 19 22 15 18 35 16 15 17 19 23 15 16 26 The sample statistics are: ?̅= 20.85, ? = 6.76. Can we infer, at the 5% significance...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT