The Airport Transit Authority wants to estimate, with 95% confidence, the proportion of adults that they have never flown in an airplane. It is desired the estimate be accurate to within 3% of the population proportion. The minimum sample size needed is closest to a) 1225 b) 1692 c) 2401 d) 49 e) 1068
Solution :
Given that,
= 0.5
1 - = 1 - 0.5 = 0.5
Margin of error = E = 3% = 0.03
At 95% confidence level the z is ,
= 1 - 95% = 1 - 0.95 = 0.05
/ 2 = 0.05 / 2 = 0.025
Z/2 = Z0.025 = 1.96
Sample size = ( Z/2 / E)2 * * (1 - )
= (1.96 /0.03)2 * 0.5 * 0.5
= 1067.11 = 1068
Sample size = n = 1068
Option e) is correct .
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