Question

A manufacturer claims that the mean lifetime of its lithium batteries is 902 hours. A homeowner selects 25 of these batteries and finds the mean lifetime to be 881 hours with a standard deviation of 83 hours. Test the manufacturer's claim. Use α = 0.05.

Answer #1

A manufacturer claims that the mean lifetime of its lithium
batteries is less than 1200 hours. A homeowner randomly selects 35
of these batteries and finds the mean lifetime to be 1180 hours
with a standard deviation of 80 hours. Test the manufacturers
claim. Use α = 0.05.

A manufacturer claims that the mean lifetime of its lithium
batteries is less than 1500 hours. A homeowner selects 25 of these
batteries and finds the mean lifetime to be 1480 hours with a
standard deviation of 80 hours. Test the manufacturer's claim.
Use α = 0.10.
A.
P-value = 0.112 > 0.10; do not reject H0; There is not enough
evidence support the claim, that mean is less than 1500.
B.
P-value = 0.112 > 0.05; do not reject...

A manufacturer claims that the mean lifetime of its lithium
batteries is less than 1120 hours. A homeowner selects 25 of these
batteries and finds the mean lifetime to be 1100 hours with a
standard deviation of 75 hours. Test the manufacturer's claim.
Use α = 0.01.
A. P-value = 0.110 > 0.01; do not reject H0; There is not
enough evidence support the claim, that mean is less than 1120.
B. P-value = 0.097 > 0.01; do not reject...

A manufacturer claims that the mean lifetime of its lithium
batteries is less than 1520 hours. A homeowner selects 27 of these
batteries and finds the mean lifetime to be 1498 hours with a
standard deviation of 76 hours. Test the manufacturer's claim. Use
α = 0.10.
A. P-value = 0.112 > 0.02; do not reject H0; There is not
enough evidence support the claim, that mean is less than 1500.
B. P-value = 0.072 > 0.05; do not reject...

A manufacturer claims that the mean life time of its lithium
batteries is 1500 hours . A home owner selects 30 of these
batteries and finds the mean lifetime to be 1470 hours with a
standard deviation of 80 hours. Test the manufacturer's claim.
Use=0.05. Round the test statistic to the nearest thousandth.
a) Hypothesis:
b)Critical value (t critical):
c)Test statistic (tstat) and the decision about the test
statistic:(reject or fail to reject Ho):
d)Conclusion that results from the decision...

A manufacturer claims that the mean lifetime of its fluorescent
bulbs is 1500 hours. A homeowner selects 40 bulbs and finds the
mean lifetime to be 1490 hours with a population standard deviation
of 80 hours. Test the manufacturers claim. Use a=0.05. Show graph
as well.

1. A manufacturer claims that the mean lifetime of its
fluorescent bulbs is 1500 hours. A homeowner selects 40 bulbs and
finds the mean lifetime to be 1480 hours with a population standard
deviation of 80 hours. Test the manufacturer's claim. Use alpha
equal to 0.05. State the sample mean and the population standard
deviation.
2. Using problem in number 1. Choose the correct hypotheses.
3. Using the problem in number 1. State the critical
value(s).
4. Using the problem...

Identify the null hypothesis, alternative hypothesis, test
statistic, P-value, conclusion about the null hypothesis, and final
conclusion that addresses the original claim.
A manufacturer claims that the mean lifetime of its fluorescent
bulbs is 1000 hours. A homeowner selects 25 bulbs and finds the
mean lifetime to be 980 hours with a standard deviation of 80
hours. If α = 0.05, test the manufacturer's claim.

A manufacture of car batteries claims its new batteries will
have a mean lifetime of 4 years. A random sample of 35 batteries
found the mean lifetime to be 3.91 years. If the population
standard deviation is known to be 0.22 years; is there enough
evidence, at the 0.05 significance level, to suggest the mean
lifetime is less than 4 years?.

1. A manufacturer claims that its rechargeable batteries are
good for an average 1,000 charges with a standard deviation of 25
charges. A random sample of 20 batteries has a mean life of 992
charges. Perform an appropriate hypothesis test with α = 0.05,
assuming the distribution of the number of recharges is
approximately normal. Hypothesis:
Test statistic:
p-value:
Conclusion:
Interpretation:

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