patient account division has collected data on the age of accounts receivables. The data collected indicate that the age of the accounts follows a normal distribution with mean 34 days and standard deviation 8 days. What proportion of the accounts are between 20 and 30 days old?
Solution :
Given that ,
mean = = 34
standard deviation = = 8
P(20 < x < 30) = P((20 - 34)/ 8) < (x - ) / < (30 - 34) / 8) )
= P(-1.75 < z < -0.5)
= P(z < -0.5) - P(z < -1.75)
= 0.3085 -0.0401
= 0.2684
The proportion of the accounts are between 20 and 30 days old is 0.2684
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