Question

Question 2) The density of random variable X is f(x) =
15(x^{2}−36)(64−x^{2}) / 3904 for 6 ≤ x ≤ 8 and 0
otherwise. Do computations using the R integrate function.

a) Find the probability that X > 7:

b) Find the probability that 6.5 < X < 7.5:

e) Find the probability that x is within one standard deviation of its expected value:

f) In the following paste your R script for this problem:

Answer #1

Part A
The variable X(random variable) has a density function of the
following
f(x) = {5e-5x if 0<= x < infinity and 0
otherwise}
Calculate E(ex)
Part B
Let X be a continuous random variable with probability density
function
f (x) = {6/x2 if 2<x<3 and 0 otherwise }
Find E (ln (X)).
.

Let X be a random variable with probability density function
f(x) = {3/10x(3-x) if 0<=x<=2
.........{0 otherwise
a) Find the standard deviation of X to four decimal
places.
b) Find the mean of X to four decimal places.
c) Let y=x2 find the probability density function
fy of Y.

Problem #3. X is a random variable with an exponential
distribution with rate λ = 7 Thus the pdf of X is f(x) = λ
e−λx for 0 ≤ x where λ = 7.
a) Using the f(x) above and the R integrate function calculate the
expected value of X.
b) Using the f(x) above and the R integrate function calculate the
expected value of X2
c) Using the dexp function and the R integrate command calculate
the expected value...

The random variable X has probability density function:
f(x) =
ke^(−x) 0 ≤ x ≤ ln 2
0 otherwise
Part a: Determine the value of k.
Part b: Find F(x), the cumulative distribution function of X.
Part c: Find E[X].
Part d: Find the variance and standard deviation of X.
All work must be shown for this question. R-Studio should not be
used.

Let X be the random variable with probability density function
f(x) = 0.5x for 0 ≤ x ≤ 2 and zero otherwise. Find the
mean and standard deviation of the random variable X.

1. f is a probability density function for the random
variable X defined on the given interval. Find the
indicated probabilities.
f(x) = 1/36(9 − x2); [−3, 3]
(a) P(−1 ≤ X ≤ 1)(9 −
x2); [−3, 3]
(b) P(X ≤ 0)
(c) P(X > −1)
(d) P(X = 0)
2. Find the value of the constant k such that the
function is a probability density function on the indicated
interval.
f(x) = kx2; [0,
3]
k=

1 (a) Let f(x) be the probability density function of a
continuous random variable X defined by
f(x) = b(1 - x2), -1 < x < 1,
for some constant b. Determine the value of b.
1 (b) Find the distribution function F(x) of X . Enter the value
of F(0.5) as the answer to this question.

Let X be a random variable with density function f(x) = 2 5 x
for x ∈ [2, 3] and f(x) = 0, otherwise. (a) (6 pts) Compute E[(X −
2)3 ] without attempting to find the density function of Y = (X −
2)3 . (b) (6 pts) Find the density function of Y = (X − 2)3

Let the probability density function of the random variable X be
f(x) = { e ^2x if x ≤ 0 ;1 /x ^2 if x ≥ 2 ; 0 otherwise}
Find the cumulative distribution function (cdf) of X.

suppose x is a continuous random variable with probability
density function f(x)= (x^2)/9 if 0<x<3 0 otherwise
find the mean and variance of x

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