6) A certain standardized test has scores which range from 0 to 500, with decimal scores possible. Scores on the exam are normally distributed with a mean of 304 and a standard deviation of 42.
What proportion of students taking the exam receive a score that is within 74 points of the mean?
Round your answer to 4 decimal places.
Given,
= 304 , = 42
We convert this to standard normal as
P(X < x) = P(Z < ( x - ) / )
We have to calculate P ( 304 - 74 < X < 304 + 74) = ?
That is
P(230 < X < 378) = ?
P(230 < X < 378) = P(X < 378) - P(X < 230)
= P(Z < ( 378 - 304) / 42) - P(Z < ( 230 - 304) / 42)
= P(Z < 1.76) - P(Z < -1.76)
= 0.9608 - 0.0392 (From Z table)
= 0.9216
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