Question

Let Z be the standard normal random variable. What is P(Z<-0.38)?

		0.0571
		0.0918
		0.1401
		0.3520
		None of the above

Answer 1

Here in this scenario we have to find the z score below -0.38.

That means we have to calculate the P(X<-0.38).

i.e P(Z<-0.38) = 1- P(Z>-0.38). Are same.

We computed the P (Z>-0.38) as below,

Here the probability is calculated using Standerd normal z-table.

Note that area of remaining part is P (Z<-0.38).

P(Z<-0.38) = 0.3520.

Other options are incorrect .

Thank you.