Assume the heights of men are normally distributed, with mean 73 inches and standard deviation 4 inches. If a random sample of nine men is selected, what is the probability that the mean height is between 72 and 74 inches? (Use 3 decimal places.)
Given,
= 73, = 4
Using central limit theorem,
P( < x) = P(Z < ( x - ) / ( / sqrt(n) ) )
So,
P(72 < < 74) = P( < 4) - P( < 72)
= P(Z < (74 - 73) / (4 / sqrt(9) ) ) - P(Z < (72 - 73) / (4 / sqrt(9) ) )
= P(Z < 0.75) - P(Z < -0.75)
= 0.7734 - 0.2266 (From Z table)
= 0.547
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