Question

Collette is​ self-employed and sells cookware at home parties. She wants to estimate the average amount a client spends at each party. A random sample of 35 receipts found the mean to be ​$35.39 with a standard deviation of ​$4.82. Find a 95​% confidence interval for the average amount spent by all her clients.  

​A) Confidence​ Interval: ( nothing ​, nothing ​) ​(round each interval limit to two decimal​ places) ​

B) In the SHOW YOUR WORK​ area, interpret the confidence interval.​ (You do not need to show the StatCrunch​ output, just the​ interpretation.) ​

C) If Party City has a mean of​ $33.92 per​ receipt, is Collette doing better or worse than Party​ City?

A. Collette is doing worse because​ $33.92 is above the interval. B. Collette is doing better because​ $33.92 is below the interval.

C. Collette is doing better because the​ $33.92 is below the mean for her.

D. One cannot tell because​ $33.92 is within the interval.

Answer 1

B) Interpretation : Collette is 95 % confident that the average amount spent by all her clients is between ( 33.73 , 37.05 ) 

C) Here Party City has a mean of​ $33.92 per​ receipt. Which is within the interval hence we can say that -  

 D. One cannot tell because​ $33.92 is within the interval.

Hope this will help you. Thank you :)