The manufacturer of cans of salmon that are supposed to have a net weight of 6 ounces tells you that the net weight is actually a normal random variable with a mean of 6.2 ounces and a standard deviation of 0.11 ounce. Suppose that you draw a random sample of 37 cans. Find the probability that the mean weight of the sample is less than 6.19 ounces.
Solution :
Given that ,
mean = = 6.2
standard deviation = = 0.11
n = 37
= 6.2
= / n = 0.11/ 37=0.018
P( < 6.19) = P[( - ) / < (6.19-6.2) / 0.018]
= P(z < -0.56)
Using z table
probability = 0.2827
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