In a survey, 28 people were asked how much they spent on their
auto insurance. The results were roughly bell-shaped with a mean of
$1092 and standard deviation of $183. Estimate how much typical
drivers would spend on their auto insurances (use a 99% confidence
level).
Confidence interval =
Solution :
(a)
t /2,df = 2.771
Margin of error = E = t/2,df * (s /n)
= 2.771 * (183 / 28)
Margin of error = E = 96
The 99% confidence interval estimate of the population mean is,
- E < < + E
1092 - 96 < < 1092 + 96
996 < < 1188
(999 , 1188)
(b)
E
1092 96
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