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The probability of missing 4,3,2,1 questions on any given quiz .2,.3,.4,.1 What is the probability of...

The probability of missing 4,3,2,1 questions on any given quiz .2,.3,.4,.1 What is the probability of taking 8 quizes and getting the following: 3 quizzes with 4 wrong, 2 quizzes with 3 wrong,1 quiz with 2 wrong, and 2 quizzes with 1 wrong? If possible could you show the excel formula

Group of answer choices

A. 0.333

B. 0.095

C. 0.0048

D. 0.210

Math   Statistics-And-Probability   
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Answer #1

Probability of taking 8 quizes and getting the following: 3 quizzes with 4 wrong, 2 quizzes with 3 wrong,1 quiz with 2 wrong, and 2 quizzes with 1 wrong is computed here as:

= Number of ways to select 3 out of 8 quizzes with 4 wrong * Number of ways to select 2 quizzes out of remaining 5 quizzes with 3 wrong * Number of ways to select 1 quiz from 3 quizzes with 2 wrong * Probability that those 3 selected have 4 wrong * Probability that those 2 quizzes are selected have 3 wrong each * Probability that the one selected has 2 wrong * Probability that that the last 2 quizzes have 1 wrong each

Therefore 0.0048 is the required probability here.

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