Question

In a survey of 2300 T.V. viewers, 690 said they watch network news programs. Find the...

In a survey of 2300 T.V. viewers, 690 said they watch network news programs. Find the margin of error for the 95% confidence interval used to estimate the population proportion.

Homework Answers

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
In a survey, 90 people were asked if they received at least some of their news...
In a survey, 90 people were asked if they received at least some of their news from social media. 61 responded Yes. (a) What is the 95% confidence interval for the proportion of people in the population who receive at least some of their news from social media? (b) Working at the 95% confidence level, how large a sample would be necessary to estimate the population proportion with a margin of error of ±0.02? Assume a planning value of p∗...
A survey of 800 randomly selected senior citizens showed that 55% said they planned to watch...
A survey of 800 randomly selected senior citizens showed that 55% said they planned to watch an upcoming political debate on television. The margin of error for the 95% confidence interval is 3.5 percentage points. Does the confidence interval support the claim that the majority of senior citizens plan to watch the upcoming political debate on television? Explain why or why not.
A survey asked subjects if they would be willing to accept cuts in their standard of...
A survey asked subjects if they would be willing to accept cuts in their standard of living to protect the environment, 344 of 1170 subjects said yes. a. Estimate the population proportion who would answer yes. b. Find the margin of error for a 95% confidence interval for this estimate. c. Find a 95% confidence interval for that proportion. d. Interpret the confidence interval in context.
In a survey of 1000 large corporations, 258 said that, given a choice between a job...
In a survey of 1000 large corporations, 258 said that, given a choice between a job candidate who smokes and an equally qualified nonsmoker, the nonsmoker would get the job. (a) Let p represent the proportion of all corporations preferring a nonsmoking candidate. Find a point estimate for p. (Round your answer to four decimal places.) (b) Find a 0.95 confidence interval for p. (Round your answers to three decimal places.) lower limit     upper limit     (c) As a news writer,...
A polling organization conducts a poll by making a random survey of 2300 people. Estimate the...
A polling organization conducts a poll by making a random survey of 2300 people. Estimate the margin of error at a confidence level of 95% using the rule of thumb for the margin of error. Round your answer as a percentage to one decimal place.
When a survey asked subjects whether they would be willing to accept cuts in their standard...
When a survey asked subjects whether they would be willing to accept cuts in their standard of living to protect the​ environment, 354354 of 11601160subjects said yes. a. Find the point estimate of the proportion of the population who would answer yes. b.Find the margin of error for a​ 95% confidence interval. c. Construct the​ 95% confidence interval for the population proportion. What do the numbers in this interval​ represent? d. State and check the assumptions needed for the interval...
A 2011 NBC News survey found that 83% of a sample of 4528 American teens said...
A 2011 NBC News survey found that 83% of a sample of 4528 American teens said they owned an MP3 player such as an iPod. Assume that the sample was an SRS. Find the 90% confidence interval (± ± 0.0001) for the proportion of all American teens who own an MP3 player. The 90% confidence interval is from to
1. A poll of 2234 U.S. adults found that 31% regularly used Facebook as a news...
1. A poll of 2234 U.S. adults found that 31% regularly used Facebook as a news source. Find the margin of error and confidence interval for the percentage of U.S. adults who regularly use Facebook as a news source, at the 90% level of confidence. Round all answers to 2 decimal places. Margin of Error (as a percentage): Confidence Interval: % to % Find the margin of error and confidence interval for the percentage of U.S. adults who regularly use...
In a survey of 920 Canadian adults, 780 say that the energy situation in Canada is...
In a survey of 920 Canadian adults, 780 say that the energy situation in Canada is very or fairly serious. 1. Find the point estimate for the population proportion. 2. Construct a 95% confidence interval for the population proportion. (a) The critical value: (b) The margin of error: (c) The lower limit of the interval: (d) The upper limit of the interval: 3. find the minimum sample size needed to estimate the population proportion at the 99% confidence level in...
In a survey of 1060 Canadian adults, 770 say that the energy situation in Canada is...
In a survey of 1060 Canadian adults, 770 say that the energy situation in Canada is very or fairly serious. 1. Find the point estimate for the population proportion. 2. Construct a 95% confidence interval for the population proportion. (a) The critical value: (b) The margin of error (c) The lower limit of the interval: (d) The upper limit of the interval: 3. find the minimum sample size needed to estimate the population proportion at the 99% confidence level in...