Question

Suppose X has a normal distribution with mean 3 and standard deviation 1. The 95th percentile of this distribution is

Group of answer choices

4.28

-4.28

4.94

-4.64

4.64

2.

Suppose X = 5 is a measurement from a normal population with mean 2 and standard deviation 3. The corresponding Z-score is

Group of answer choices

2

5

0

1

3

3. Suppose X is a standard normal random variable. Among other things this implies that the mean of X is 0 and its standard deviation is

Group of answer choices

-1

0

2

4

1

Answer 1

1). X ~ N (3,1)

let a be the 95 th percentile .

according to the problem:

[ in any blank cell of excel type =NORMSINV(0.95) ]

the 95 th percentile = 4.64

2).given data are:-

the corresponding Z score is:-

3).the standard normal variable has mean of X is 0 and its standard deviation is = 1

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