To compare two kinds of bumper guards, 6 of each kind were mounted on a certain kind of compact car. Then each car was run into a concrete wall at 5 miles per hour, and the following are the costs of the repairs (in dollars)
Bumper guard 1: 107 148 123 165 102 119
Bumper guard 2: 134 115 112 151 133 129 Use the 0.01 level of significance to test whether the difference between the two sample means is significant.
Guard 1 | Guard 2 | |
127.33 | 129.00 | mean |
24.45 | 14.21 | std. dev. |
6 | 6 | n |
To Test :-
H0 :- µ1 = µ2
H1 :- µ1 ≠ µ2
Test Statistic :-
t = (X̅1 - X̅2) / SP √ ( ( 1 / n1) + (1 / n2))
Sp = 19.998
t = - 0.14
P value = 2 * P ( t > 0.14 ) = 0.8881
Reject null hypothesis if P value < α = 0.01 level of
significance
P - value = 0.8881 > 0.01, hence we fail to reject null
hypothesis
Conclusion :- Fail to reject null hypothesis
There is no sufficient evidence to conclude that the difference is significant.
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