Question

**Teenage Tobacco Use:** In a random sample of 900
teenagers, 168 had used tobacco of some form in the last year. The
managers of an anti-tobacco campaign want to claim that less than
20% of all teenagers use tobacco. Test their claim at the 0.10
significance level.

(a) What is the sample proportion of teenagers who use tobacco?
**Round your answer to 3 decimal places.**

*p̂* =

(b) What is the test statistic? **Round your answer to 2
decimal places.**

*z* =

(c) What is the P-value of the test statistic? **Round your
answer to 4 decimal places.**

P-value =

(d) What is the conclusion regarding the null hypothesis?

reject *H*_{0}

fail to reject
*H*_{0}

(e) Choose the appropriate concluding statement.

The data supports the claim that less than 20% of all teenagers use tobacco.

There is not enough data to support the claim that less than 20% of all teenagers use tobacco.

We reject the claim that less than 20% of all teenagers use tobacco.

We have proven that less than 20% of all teenagers use tobacco.

Answer #1

In a random sample of 900 teenagers, 148 had used tobacco of
some form in the last year. The managers of an anti-tobacco
campaign want to claim that less than 20% of all teenagers use
tobacco. Test their claim at the 0.01 significance level. (a) What
is the sample proportion of teenagers who use tobacco? Round your
answer to 3 decimal places. p̂ = (b) What is the test statistic?
Round your answer to 2 decimal places. zp hat =...

Corn: In a random sample of 80 ears of corn,
farmer Carl finds that 7 of them have worms. Carl claims that less
than 20% of all his corn has worms. Test this claim at the 0.01
significance level.
(a) What is the sample proportion of corn with worms?
Round your answer to 3 decimal places.
p̂ =
(b) What is the test statistic? Round your answer to 2
decimal places.
z =
(c) What is the P-value of the...

Spam: Larry claims that more than a quarter of all his email is
spam. In a random sample of 60 of his emails, 20 of them are spam.
Test his claim at the 0.10 significance level.
(a) What is the sample proportion of spam in his email? Round
your answer to 3 decimal places. p̂ =
(b) What is the test statistic? Round your answer to 2 decimal
places. zp hat =
(c) What is the P-value of the test...

In a sample of 45 adults, the mean assembly time for a child's
swing set was 1.76 hours with a standard deviation of 0.79 hours.
The makers of the swing set claim the average assembly time is less
than 2 hours. Test their claim at the 0.01 significance level.
(a) What type of test is this?
This is a right-tailed test.
This is a two-tailed test.
This is a left-tailed test.
(b) What is the test statistic? Round your answer...

In a sample of 35 adults, the mean assembly time for a child's
swing set was 1.76 hours with a standard deviation of 0.72 hours.
The makers of the swing set claim the average assembly time is less
than 2 hours. Test their claim at the 0.01 significance level. (a)
What type of test is this? This is a two-tailed test. This is a
left-tailed test. This is a right-tailed test. (b) What is the test
statistic? Round your answer...

In Sludge County, a sample of 40 randomly selected citizens were
tested for pinworm. Of these, 9 tested positive. The CDC reports
that the U.S. average pinworm infection rate is 12%. Test the claim
that Sludge County has a pinworm infection rate that is greater
than the national average. Use a 0.01 significance level.
a) What is the sample proportion of Sludge County residents with
pinworm? Round your answer to 3 decimal places. p̂ =
(b) What is the test...

Pinworm: In Sludge County, a sample of 60 randomly selected
citizens were tested for pinworm. Of these, 14 tested positive. The
CDC reports that the U.S. average pinworm infection rate is 12%.
Test the claim that Sludge County has a pinworm infection rate that
is greater than the national average. Use a 0.01 significance
level.
(a) What is the sample proportion of Sludge County residents
with pinworm? Round your answer to 3 decimal places. p̂ =
(b) What is the...

A random sample of 20 binomial trials resulted in 8 successes.
Test the claim that the population proportion of successes does not
equal 0.50. Use a level of significance of 0.05.
(a) Can a normal distribution be used for the p̂
distribution? Explain.
Yes, np and nq are both greater than 5.No,
np and nq are both less than
5. No, np is greater than 5, but
nq is less than 5.Yes, np and nq are
both less than 5.No, nq...

Assembly Time: In a sample of 40 adults, the
mean assembly time for a child's swing set was 1.77 hours with a
standard deviation of 0.76 hours. The makers of the swing set claim
the average assembly time is less than 2 hours. Test their claim at
the 0.01 significance level.
(a) What type of test is this?
This is a left-tailed test. This is a two-tailed
test. This is a right-tailed test.
(b) What is the test statistic? Round...

Pinworm: In Sludge County, a sample of 60
randomly selected citizens were tested for pinworm. Of these, 11
tested positive. The CDC reports that the U.S. average pinworm
infection rate is 12%. Test the claim that Sludge County has a
pinworm infection rate that is greater than the national average.
Use a 0.05 significance level.
(a) What is the sample proportion of Sludge County residents
with pinworm? Round your answer to 3 decimal
places.
p̂ =
(b) What is the...

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