Question

1. Based on the information in the source table below and given an alpha level of 0.05, what would you conclude?
   

Source	SS	df	MS	F
Between-groups	100	2	50	42.02
Within-groups	50	42	1.19
Total	150	44

1. Reject the null hypothesis. The calculated F is larger than the critical value.
2. Fail to reject the null hypothesis. The calculated F is smaller than the critical value.
3. Fail to reject the null hypothesis. The calculated F is larger than the critical value.
4. Reject the null hypothesis. The calculated F is smaller than the critical value.

2. _____ can be interpreted as the proportion of variance in the dependent variable that is accounted for by the independent variable.

            

1. MS
2. R2
3. F
4. D

Answer 1

Solution:

Mean Sum of squares between- groups =

SS between groups/ 2 = 100/2= 50

Mean Sum of Squares within groups(Error) = SSE/42= 50/42= 1.1905

Variance Ratio F= MSS between groups/ MSE = 50/1.1905 = 41.999

Critical value: Tabulated F _{0. 05} for 2 and 42 d. f is 3.22

Since calculated F > tabulated F at 0.05 level of significance, Reject Null hypothesis.

Option a) is correct. Reject the null hypothesis. The calculated F is larger than the critical value.

Option c) F can be interpreted as the proportion of variance in the dependent variable that is accounted for by the independent variable.