You are performing a left-tailed test with test statistic z=−1.961z=-1.961, find the p-value accurate to 4 decimal places.
The given are :
Test Statistic z = - 1. 961
we will find the value in two ways 1 ) by excel and 2 ) by using table
1) we will use excel command to find the p value for test statistic z = -1.961 . the excel command is as follows:
' = normsdist(-1.961)' and enter the final answer is 0.0250
so the final answer is p value = 0.0250
2) using the negative z score table , look the value -1.9 in the row in the table and in column 0.06 simulteneously the value is 0.0250 and these is the p-value.
hence the final answer is p value = 0.0250
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