show data visualizations and comment .
create data visualizations before and after the results that you would present for the following:
1)Analyze the correlation for the following data:
Orifice Diameter |
Radon Released (%) |
|||
0.37 |
80 |
83 |
83 |
85 |
0.51 |
75 |
75 |
79 |
79 |
0.71 |
74 |
73 |
76 |
77 |
1.02 |
67 |
72 |
74 |
74 |
1.40 |
62 |
62 |
67 |
69 |
1.99 |
60 |
61 |
64 |
66 |
2)A company operates four machines three shifts each day. From production records, the following data on the number of breakdowns are collected:
Shift |
Machines |
|||
A |
B |
C |
D |
|
1 |
41 |
20 |
12 |
16 |
2 |
31 |
11 |
9 |
14 |
3 |
15 |
17 |
16 |
10 |
Test the hypothesis (using ? = 0.05) using the Chi-Square Test that breakdowns are independent of the shift. Find the p-value for this test.
Ans:
2)
Ho:Breakdowns are independent of the shift.
Ha:Breakdowns are not independent of the shift.
Expected count=row sum*column sum/overall toal
Observed count(fo) | |||||
Shift/Machines | A | B | C | D | Total |
1 | 41 | 20 | 12 | 16 | 89 |
2 | 31 | 11 | 9 | 14 | 65 |
3 | 15 | 17 | 16 | 10 | 58 |
Total | 87 | 48 | 37 | 40 | 212 |
Expected count(fe) | |||||
Shift/Machines | A | B | C | D | Total |
1 | 36.52 | 20.15 | 15.53 | 16.79 | 89 |
2 | 26.67 | 14.72 | 11.34 | 12.26 | 65 |
3 | 23.80 | 13.13 | 10.12 | 10.94 | 58 |
Total | 87 | 48 | 37 | 40 | 212 |
Chi square=(fo-fe)^2/fe | |||||
Shift/Machines | A | B | C | D | Total |
1 | 0.55 | 0.00 | 0.80 | 0.04 | 1.39 |
2 | 0.70 | 0.94 | 0.48 | 0.25 | 2.37 |
3 | 3.25 | 1.14 | 3.41 | 0.08 | 7.89 |
Total | 4.50 | 2.08 | 4.70 | 0.36 | 11.65 |
Test statistic:
Chi square score=11.65
df=(3-1)*(4-1)=6
p-value=CHIDIST(11.65,6)=0.0703
As,p-value>0.05,we fail to reject the null hypothesis and we can conclude that breakdowns are independent of the shift.
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