Salaries of 45 college graduates who took a statistics course in college have a mean, x, of $ 64,900 . Assuming a standard deviation, q, of $19,881 , construct a 95 % confidence interval for estimating the population mean u.
$ -----<μ< $------ round to nearest integer as needed
Solution :
sample size = n = 45
Degrees of freedom = df = n - 1 = 44
t
/2,df = 2.015
Margin of error = E = t/2,df
* (s /
n)
= 2.015 * (19881 /
45)
Margin of error = E = 5971.8
The 95% confidence interval estimate of the population mean is,
- E <
<
+ E
64900 - 5971.8 <
< 64900 + 5971.8
$58928 <
< $70872
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