Question

A client of a commercial rose grower has been keeping records on the shelf-life of a rose. The client sent the following frequency distribution to the grower.

Rose Shelf-Life

Days of Shelf-Life	Frequency fifi
1 – 6	3
7 – 12	3
13 – 18	8
19 – 24	7
25 – 30	3
3131 – 3636	22

Step 1 of 2 :  

Calculate the population mean for the shelf-life. Round your answer to two decimal places, if necessary.

Step 2 of 2 :

Calculate the population standard deviation for the shelf-life. Round your answer to two decimal places, if necessary.

Answer 1

the necessary calculation table :-

days of shelf life	frequency (fi)	class mark (xi)
1 - 6	3	(1+6)/2 = 3.5	10.5	36.75
7 - 12	3	9.5	28.5	270.75
13 - 18	8	15.5	124	1922
19 - 24	7	21.5	150.5	3235.75
25 - 30	3	27.5	82.5	2268.75
31 - 36	2	33.5	67	2244.5
	sum = 26		sum = 463	sum = 9978.5

a).the population mean for the shelf-life is :-

b). the population standard deviation for the shelf-life is :-

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