In a stat class, there are 18 juniors and 10 seniors; 6 of the seniors are females and, 12 of the juniors are males. a) Complete the following contingency table for this scenario. If a student is randomly chosen from this group: b) What is P(student is a junior)? c) What is P(student is a male and a junior)? d) What is P(student is a male or a senior)? e) What is the probability the student is a male if you know the student is a junior? f) Are the events being a junior and being a male disjoint? (You must supply a reason.) g) Are the events being a junior and being a male independent events? (You must supply a reason and show your formula used.) 11) Suppose you randomly select three students for a special assignment, selecting them one at a time. What is the probability that your first two selections are juniors and the third is a senior?
from above data:
junior | senior | total | |
male | 12 | 4 | 16 |
female | 6 | 6 | 12 |
total | 18 | 10 | 28 |
b)
P(student is a junior) =18/28=9/14
c)
What is P(student is a male and a junior) =12/28 =6/14
d)
P(student is a male or a senior) =(16+10-4)/28=22/28=11/14
e)probability the student is a male if you know the student is a junior =P(male|Junior)=12/18=2/3
f)
no as 12 common elements are there between male and junior,
g)
as P(male)=12/28=3/7 is nt equal to P(male|junior) ; therefore being a junior and being a male are not independent events
11)
probability that your first two selections are juniors and the third is a senior
=18C2*10C1/28C3 =153*10/3276 =85/182
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