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Lost-time accidents occur in a company at a mean rate of 0.6 per day. What is...

Lost-time accidents occur in a company at a mean rate of 0.6 per day. What is the probability that the number of lost-time accidents occurring over a period of 10 days will be at least 2? Round your answer to four decimal places.

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Answer #1

Solution:

Given: Lost-time accidents occur in a company at a mean rate of 0.6 per day.

We have to find:

P( the number of lost-time accidents occurring over a period of 10 days will be at least 2) =..........?

We have mean rate of 0.6 per day.

Thus mean rate for 10 days = 10 * 0.6 = 6

Thus x = the number of lost-time accidents occurring over a period of 10 days follows a Poisson distribution with parameter

Probability mass function of Poisson distribution is:

We have to find:

P( At least 2) = .......?

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