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Assume that the readings at freezing on a batch of thermometers are normally distributed with a...

Assume that the readings at freezing on a batch of thermometers are normally distributed with a mean of 0°C and a standard deviation of 1.00°C. A single thermometer is randomly selected and tested. Find P99, the 99-percentile. This is the temperature reading separating the bottom 99% from the top 1%.

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Answer:

Given that:

Assume that the readings at freezing on a batch of thermometers are normally distributed with a mean of 0°C and a standard deviation of 1.00°C. A single thermometer is randomly selected and tested.

mean() = 0

Standard deviation = 1

The z-distribution of bottom 99% is %

Using z-score formula

Temperature reading = of   percentile.

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