Question

A poll of 2,061 randomly selected adults showed that 97% of them own cell phones. The...

A poll of 2,061 randomly selected adults showed that 97% of them own cell phones. The technology display below results from a test of the claim that 94% of adults own cell phones. Use the normal distribution as an approximation to the binomial distribution, and assume a 0.01 significance level to complete parts (a) through (e). Show your work. ***Correct answers are in BOLD (how do we get those answers)

Test of p=0.94 vs p≠0.94

X= 1989, N= 2061, Sample p=0.965066, 95% CI=(0.954648, 0.975483), z-value= 4.79, p-value= 0.000

a. Is the test two-tailed, left-tailed, or right-tailed? two-tailed

b. What is the test statistic? (Round to two decimal places as needed.) 4.79

c. What is the P-value? (Round to three decimal places as needed.) 0.000

d. What is the null hypothesis and what do you conclude about it? H0:p=0.94

Choose the correct answer below:

a. Reject the null hypothesis because the P-value is less than or equal to the significance level

b. Reject the null hypothesis because the P-value is greater than the significance level

c. Fail to reject the null hypothesis because the P-value is less than or equal to the significance level

d. Fail to reject the null hypothesis because the P-value is greater than the significance level

What is the final conclusion?

a. There is not sufficient evidence to warrant rejection of the claim that 94% of adults own a cell phone.

b. There is sufficient evidence to warrant rejection of the claim that 94% of adults own a cell phone.

c. There is sufficient evidence to support the claim that 94% of adults own a cell phone.

d. There is not sufficient evidence to support the claim that 94% of adults own a cell phone

Homework Answers

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
A poll of 2,133 randomly selected adults showed that 94​% of them own cell phones. The...
A poll of 2,133 randomly selected adults showed that 94​% of them own cell phones. The technology display below results from a test of the claim that 92​% of adults own cell phones. Use the normal distribution as an approximation to the binomial​ distribution, and assume a 0.01 significance level to complete parts​ (a) through​ (e). Test of pequals 0.92vs pnot equals 0.92 Sample X N Sample p ​95% CI ​Z-Value ​P-Value 1 1996 2 comma 133 0.935771 ​(0.922098​,0.949444 ​)...
A poll of 2 comma 1172,117 randomly selected adults showed that 9191​% of them own cell...
A poll of 2 comma 1172,117 randomly selected adults showed that 9191​% of them own cell phones. The technology display below results from a test of the claim that 9393​% of adults own cell phones. Use the normal distribution as an approximation to the binomial​ distribution, and assume a 0.010.01 significance level to complete parts​ (a) through​ (e). Test of pequals=0.930.93 vs pnot equals≠0.930.93 Sample X N Sample p ​95% CI ​Z-Value ​P-Value 1 19241924 2 comma 1172,117 0.9088330.908833 ​(0.8927190.892719​,0.9249480.924948​)...
A poll of 2,024 randomly selected adults showed that 94​% of them own cell phones. The...
A poll of 2,024 randomly selected adults showed that 94​% of them own cell phones. The technology display below results from a test of the claim that 90​% of adults own cell phones. Use the normal distribution as an approximation to the binomial​ distribution, and assume a 0.01 significance level to complete parts​ (a) through​ (e). Test of pequals=0.9 vs p≠0.9 Sample X N Sample p ​95% CI ​Z-Value ​P-Value 1 1904 2,024 0.940711 ​(0.927190,0.954233) 6.11 0.000 a. Is the...
a poll of 2039 randomly selected adults showed that 96% of them own cell phones. the...
a poll of 2039 randomly selected adults showed that 96% of them own cell phones. the technology display below results from a test of a claim that 92% of adults own cell phones. use the normal distribution as an approximation to the binomial distribution, and assume a 0.01 significance level to complete parts (a) through (e) a) is the test two-tailed, left-tailed, or right-tailed b) the test statistic is ( rounded two decimals) c) the p- value ( rounded three...
A survey of 1,570 randomly selected adults showed that 541 of them have heard of a...
A survey of 1,570 randomly selected adults showed that 541 of them have heard of a new electronic reader. The accompanying technology display results from a test of the claim that 34​% of adults have heard of the new electronic reader. Use the normal distribution as an approximation to the binomial​ distribution, and assume a 0.01 significance level to complete parts​ (a) through​ (e). a. Is the test​ two-tailed, left-tailed, or​ right-tailed? Right tailed test ​Left-tailed test ​Two-tailed test b....
A poll of 2 comma 047 randomly selected adults showed that 94​% of them own cell...
A poll of 2 comma 047 randomly selected adults showed that 94​% of them own cell phones. The technology display below results from a test of the claim that 95​% of adults own cell phones. Use the normal distribution as an approximation to the binomial​ distribution, and assume a 0.01 significance level to complete parts​ (a) through​ (e). Test of pequals0.95 vs pnot equals0.95 Sample X N Sample p ​95% CI ​Z-Value ​P-Value 1 1933 2 comma 047 0.944309 ​(0.931253​,0.957365​)...
A poll of 2 comma 059 randomly selected adults showed that 93​% of them own cell...
A poll of 2 comma 059 randomly selected adults showed that 93​% of them own cell phones. The technology display below results from a test of the claim that 94​% of adults own cell phones. Use the normal distribution as an approximation to the binomial​ distribution, and assume a 0.01 significance level to complete parts​ (a) through​ (e). Test of pequals0.94 vs pnot equals0.94 Sample X N Sample p ​95% CI ​Z-Value ​P-Value 1 1909 2 comma 059 0.927149 ​(0.912396​,0.941902​)...
A poll of 2 comma 085 randomly selected adults showed that 94​% of them own cell...
A poll of 2 comma 085 randomly selected adults showed that 94​% of them own cell phones. The technology display below results from a test of the claim that 91​% of adults own cell phones. Use the normal distribution as an approximation to the binomial​ distribution, and assume a 0.05 significance level to complete parts​ (a) through​ (e). Test of pequals0.91 vs pnot equals0.91 Sample X N Sample p ​95% CI ​Z-Value ​P-Value 1 1957 2 comma 085 0.938609 ​(0.928306​,0.948913​)
In a recent poll of 745 randomly selected​ adults, 586 said that it is morally wrong...
In a recent poll of 745 randomly selected​ adults, 586 said that it is morally wrong to not report all income on tax returns. Use a 0.01 significance level to test the claim that 75% of adults say that it is morally wrong to not report all income on tax returns. Identify the null​ hypothesis, alternative​ hypothesis, test​ statistic, P-value, conclusion about the null​ hypothesis, and final conclusion that addresses the original claim. Use the​ P-value method. Use the normal...
Assume that adults were randomly selected for a poll. They were asked if they​ "favor or...
Assume that adults were randomly selected for a poll. They were asked if they​ "favor or oppose using federal tax dollars to fund medical research using stem cells obtained from human​ embryos." Of those​ polled, 481 were in​ favor, 397 were​ opposed, and 120 were unsure. A politician claims that people​ don't really understand the stem cell issue and their responses to such questions are random responses equivalent to a coin toss. Exclude the 120 subjects who said that they...