Question

The probability that a contractor will win a bid for contract A is 0.45; the probability that the contractor will win a bid for contract B is 0.25. The two bids are believed to be independent of each other. What is the probability that the contractor will win at least one of the two bids?

Group of answer choices

0.70

0.20

0.1125

0.5875

0.5556

The probability that I get job A is 0.45; the probability that I get job B is 0.60 and the probability that I get both the jobs is 0.30. The probability that I get at least one job offer is:

Group of answer choices

0.30

0

1

0.55

0.75

Answer 1

Solution:

Question 1)

Given: The probability that a contractor will win a bid for contract A is 0.45;

the probability that the contractor will win a bid for contract B is 0.25.

Thus P(A) =0.45 and P(B) =0.25

The two bids are believed to be independent of each other.

Thus P(A and B) = P(A)XP(B) =0.45 X 0.25 = 0.1125

We have to find:

P( the contractor will win at least one of the two bids) =...........?

That is:

P(A or B) = .............?

P(A or B) = P(A) + P(B) - P( A and B)

P(A or B) = 0.45 + 0.25 - 0.1125

P(A or B) = 0.5875

Question 2)

Given:

P(A)= 0.45

P(B) = 0.60

P( A and B ) = 0.30

Find:
P(I get at least one job offer) =............?

P(A or B) =P(A) + P(B) - P( A and B)

P(A or B) = 0.45 + 0.60 - 0.30

P(A or B) = 0.75