Question

Mean= 4.7875 Standard deviation (sample)= 0.908387 A) Find the percent of the data that lie within...

Mean= 4.7875

Standard deviation (sample)= 0.908387

A) Find the percent of the data that lie within 1.5 standard deviations of the mean.

B) Find the interquartile range. (?3?1)(Q_3-Q_1)

Data

2.9    4.3    5.4    4.9

5.9    5.8    3.9    5.1

5.4    6.1    4.2    5.5

3.5    4.4    4.3    5.0

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Homework Answers

Answer #1

Solution-A:

1.5 standard deviations of the mean is

mean-1.5sd=4.7875-1.5*0.908387=3.424919

mean+1.5sd=4.7875+1.5*0.908387= 6.15008

values thtat fill between 3.424919 and  6.15008

except 2.9 all data lies within 3.424919 and 6.15008

percent of the data that lie within 1.5 standard deviations of the mean.=11/12*100=0.9166667*100=91.67%

Solution-B:

Q1=4.275

Q3=5.425

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