Question
Mean= 4.7875 Standard deviation (sample)= 0.908387 A) Find the percent of the data that lie within...
Mean= 4.7875
Standard deviation (sample)= 0.908387
A) Find the percent of the data that lie within 1.5 standard deviations of the mean.
B) Find the interquartile range. (?3−?1)(Q_3-Q_1)
Data
2.9 4.3 5.4 4.9
5.9 5.8 3.9 5.1
5.4 6.1 4.2 5.5
3.5 4.4 4.3 5.0
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Homework Answers
Answer #1
Solution-A:
1.5 standard deviations of the mean is
mean-1.5sd=4.7875-1.5*0.908387=3.424919
mean+1.5sd=4.7875+1.5*0.908387= 6.15008
values thtat fill between 3.424919 and 6.15008
except 2.9 all data lies within 3.424919 and 6.15008
percent of the data that lie within 1.5 standard deviations of the mean.=11/12*100=0.9166667*100=91.67%
Solution-B:
Q1=4.275
Q3=5.425
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