Question

Mean= 4.7875

Standard deviation (sample)= 0.908387

A) Find the percent of the data that lie within 1.5 standard deviations of the mean.

B) Find the interquartile range.
*(**?**3**−**?**1**)*(Q_3-Q_1)

Data

2.9 4.3 5.4 4.9

5.9 5.8 3.9 5.1

5.4 6.1 4.2 5.5

3.5 4.4 4.3 5.0

NEED STEP BY STEP ON HOW TO SOLVE **USING
EXCEL**

Answer #1

Solution-A:

1.5 standard deviations of the mean is

mean-1.5sd=4.7875-1.5*0.908387=3.424919

mean+1.5sd=4.7875+1.5*0.908387= 6.15008

values thtat fill between 3.424919 and 6.15008

except 2.9 all data lies within 3.424919 and 6.15008

percent of the data that lie within 1.5 standard deviations of the mean.=11/12*100=0.9166667*100=91.67%

Solution-B:

Q1=4.275

Q3=5.425

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3.1
4.9
2.8
3.6
2.5
4.5
3.5
3.7
4.1
4.9
2.9
2.1
3.5
4.0
3.7
2.7
4.0
4.4
3.7
4.2
3.8
6.2
2.5
2.9
2.8
5.1
1.8
5.6
2.2
3.4
2.5
3.6
5.1
4.8
1.6
3.6
6.1
4.7
3.9
3.9
4.3
5.7
3.7
4.6
4.0
5.6
4.9
4.2
3.1
3.9
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Day
A
B
C
D
1
7.2
8.4
7.9
4.9
2
5.6
8.7
3.3
4.2
3
5.5
7.3
3.2
6.0
4
4.4
8.0
5.4
7.4
5
9.7
4.6
4.8
5.8
6
8.3
8.9
9.1
6.2
7
4.7
6.6
5.3
5.8
8
8.8
5.5
8.4
6.9
9
5.7
4.7
4.1
4.6
10
3.7
4.0
3.0
5.2
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5.9
6.1
6.1
5.1
5.5
5.3
5.5
6.9
5.0
4.9
6.0
4.8
6.1
5.6
5.1
5.6
4.8
5.4
5.1
5.1
5.9
5.2
5.7
5.4
4.5
6.4
5.3
5.5
6.7
5.7
4.9
4.8
5.9
5.1
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1.5
1.9
1.4
1.5
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L2
L3
L4
L5
L6
4.7
72
4.5
2.1
21
9.9
3.2
77
5.8
1.3
16
11.3
5.1
65
3.7
2.8
10
11.4
4.7
85
4.9
1.5
10
9
3.0
68
4.3
1.0
11
10.1
3.4
83
4.7
8.2
9
8.2
4.4
73
5.8
1.9
13
8.9
3.5
79
3.2
9.5
12
9.9
4.5
72
3.0
3.2
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10.5
5.8
81
5.1
1.3
29
8.6
3.7
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3.6
4.4
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7.8
4.9
91
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3.8
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4.6
3.3
3.6
3.8
3.4
3.8
4.4
4.7
3.7
3.4
4.4
4.3
4.0
3.8
4.4
4.5
3.5
4.1
4.3
3.9
3.5
3.4
3.8
3.9
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