Question

A population has a mean of 239 and a standard deviation of 128. If a sample...

A population has a mean of 239 and a standard deviation of 128. If a sample of size 6 is taken, what is the probability the sample mean is less than 288.1? Enter your answer as a decimal to 3 decimal places.

A population has a mean of 474 and a standard deviation of 125. If a sample of size 8 is taken, what is the probability the sample mean is less than 536.4? Enter your answer as a decimal to 3 decimal places.

Homework Answers

Answer #1

Given,

= 239 , = 128

Using central limit theorem,

P( < x) = P(Z < (x - ) / ( / sqrt(n) ) )  

a)

P( < 288.1) = P(Z < ( 288.1 - 239) / (128 / sqrt(6)) )

= P(Z < 0.94 )

= 0.826

b)

P( < 536.4) = P(Z < ( 536.4 - 474) / (125 / sqrt(8)) )

= P(Z < 1.41)

= 0.921

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
A population has a mean of 220 and a standard deviation of 120. If a sample...
A population has a mean of 220 and a standard deviation of 120. If a sample of size 6 is taken, what is the probability the sample mean is greater than 291.6? Enter your answer as a decimal to 3 decimal places. A population has a mean of 486 and a standard deviation of 121. If a sample of size 10 is taken, what is the probability the sample mean is greater than 506.4? Enter your answer as a decimal...
A population has a mean of 161.2 and a standard deviation of 9.6. A sample of...
A population has a mean of 161.2 and a standard deviation of 9.6. A sample of size 13 is taken from this population. What is the standard deviation of the sampling distribution of the mean?  Enter your answer to 3 decimal places. We have two random variables, A and B. A has a mean of 89.6 and a standard deviation of 37.7. B has a mean of 23.6 and a standard deviation of 15.1. If we create a new random variable...
A population has a mean of 300 and a standard deviation of 80. Suppose a sample...
A population has a mean of 300 and a standard deviation of 80. Suppose a sample of size 125 is selected and  is used to estimate . Use z-table. What is the probability that the sample mean will be within +/- 8 of the population mean (to 4 decimals)? (Round z value in intermediate calculations to 2 decimal places.)    What is the probability that the sample mean will be within +/- 11 of the population mean (to 4 decimals)? (Round...
A population has a mean of 300 and a standard deviation of 70. Suppose a sample...
A population has a mean of 300 and a standard deviation of 70. Suppose a sample of size 125 is selected and  is used to estimate . Use z-table. What is the probability that the sample mean will be within +/- 3 of the population mean (to 4 decimals)? (Round z value in intermediate calculations to 2 decimal places.) What is the probability that the sample mean will be within +/- 10 of the population mean (to 4 decimals)? (Round z...
A population has a mean of 200 and a standard deviation of 90. Suppose a sample...
A population has a mean of 200 and a standard deviation of 90. Suppose a sample of size 125 is selected and is used to estimate . Use z-table. a. What is the probability that the sample mean will be within +/- 9 of the population mean (to 4 decimals)? (Round z value in intermediate calculations to 2 decimal places.) b. What is the probability that the sample mean will be within +/- 11 of the population mean (to 4...
A population has a mean of 75 and a standard deviation of 32. Suppose a random...
A population has a mean of 75 and a standard deviation of 32. Suppose a random sample size of 80 will be taken. 1. What are the expected value and the standard deviation of the sample mean x ̅? 2. Describe the probability distribution to x ̅. Draw a graph of this probability distribution of x ̅ with its mean and standard deviation. 3. What is the probability that the sample mean is greater than 85? What is the probability...
A population has a mean of 300 and a standard deviation of 70. Suppose a sample...
A population has a mean of 300 and a standard deviation of 70. Suppose a sample of size 100 is selected and  is used to estimate . Use z-table. What is the probability that the sample mean will be within +/- 8 of the population mean (to 4 decimals)? (Round z value in intermediate calculations to 2 decimal places.) What is the probability that the sample mean will be within +/- 18 of the population mean (to 4 decimals)? (Round z...
A population has a mean of 200 and a standard deviation of 60. Suppose a sample...
A population has a mean of 200 and a standard deviation of 60. Suppose a sample of size 100 is selected and  is used to estimate . Use z-table. What is the probability that the sample mean will be within +/- 6 of the population mean (to 4 decimals)? (Round z value in intermediate calculations to 2 decimal places.) What is the probability that the sample mean will be within +/- 17 of the population mean (to 4 decimals)? (Round z...
A population has a mean of 300 and a standard deviation of 70. Suppose a sample...
A population has a mean of 300 and a standard deviation of 70. Suppose a sample of size 100 is selected and  is used to estimate . Use z-table. A. What is the probability that the sample mean will be within +/- 8 of the population mean (to 4 decimals)? (Round z value in intermediate calculations to 2 decimal places.) B. What is the probability that the sample mean will be within +/- 10 of the population mean (to 4 decimals)?...
A population has mean 72 and standard deviation 6. Find the mean and standard deviation of...
A population has mean 72 and standard deviation 6. Find the mean and standard deviation of X for samples of size 45. Find the probability that the mean of a sample of size 45 will differ from the population mean 72 by at least 2 units, that is, is either less than 70 or more than 74. (Hint: One way to solve the problem is to first find the probability of the complementary event.)
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT