Question

Uninsured: It is estimated that 19% of all adults in the U.S. are uninsured. We will assume this is accurate. You take a random sample of 300 adults seen by a certain clinic and find that 42 (about 14%) are uninsured.

(a) Assume the quoted value of 19% for uninsured adults is accurate. What what is the mean number of uninsured adults in all random samples of size 300? Round your answer to one decimal place.

(b) What is the standard deviation? Round your answer to one decimal place.

(c) In your survey you found 42 of the 300 U.S. adults are uninsured. With respect to the mean and standard deviation found in parts (a) & (b) respectively, what is the z-score for this many uninsured adults? Round your answer to two decimal places.

(d) Assuming the quoted value of 19% for uninsured adults is accurate. Would 42 out of 300 be considered unusual?

Yes, that is an unusual number of uninsured adults.

No, that is not unusual.

Answer #1

Solution :

Given that,

p = 0.19

q = 1 - p = 1 - 0.19 = 0.81

n = 300

Using binomial distribution,

a) Mean = = n * p = 300 * 0.19 = 57

b) Standard deviation = = n * p * q = 300 * 0.19 * 0.81 = 6.8

c) x = 42

Using z-score formula,

z = x - /

z = 42 - 57 / 6.8

z = -2.21

d) Yes, that is an unusual number of uninsured adults.because z-score -2.21 outside the -2.00 and 2.00 z-score

1. In May 2019, 69% of all adults in the U.S. said they use
Facebook. We then took a random sample of 22 American adults.
probability that exactly half of our sample use Facebook?
probability that at least 10 of our sample use Facebook?
mean and standard deviation for the number of adults that use
Facebook for the sample?

Binomial distribution) Twelve percent of U.S.
adults eat fast food four to six times per week. You randomly
select 12 U.S. adults. The random variable (x) is the number of
U.S. adults who eat fast food four to six times per week.
a. Find the average number of U.S. adults who eat fast food four to
six times per week. Round
your answer to two decimal places. Blank 1
b. Find the variance of the number of U.S. adults who...

TV sets: According to the Nielsen Company, the
mean number of TV sets in a U.S. household in 2013 was 2.24. Assume
the standard deviation is 1.3. A sample of 90 households is
drawn.
A) What is the probability that the sample mean number of TV
sets is greater than 2? Round your answer to four decimal
places.
B) What is the probability that the sample mean number of TV
sets is between 2.5and 3? Round your answer to four...

According to a survey in a country, 22% of adults do not own a
credit card. Suppose a simple random sample of 300 adults is
obtained
a) What is the probability that in a random sample of 300
adults, between 19% and 24% do not own a credit card? The
probability is ____. (Round to four decimal places as
needed.)
b) If 100 different random samples of 300 adults were obtained,
one would expect nothing to result in between 19%...

TV sets: According to the Nielsen Company, the mean number of TV
sets in a U.S. household in 2013 was 2.24. Assume the standard
deviation is1.1 . A sample of 80 households is drawn. Use the
Cumulative Normal Distribution Table if needed.
A. What is the probability that the sample mean number of TV
sets is greater than 2? Round your answer to four decimal
places.
B. What is the probability that the sample mean number of TV
sets is...

In a sample of 2091 U.S. adults, 388 said Franklin Roosevelt
was the best president since World War II. Two U.S. adults are
selected at random from the population of all U.S. adults without
replacement. Assuming the sample is representative of all U.S.
adults, complete parts (a) through (d)
(a) Find the probability that both adults say Franklin Roosevelt
was the best president since World War II. (ROUND TO THREE DECIMAL
PLACES AS NEEDED)
(b) Find the probability that neither...

It is estimated 30% of all adults in United States invest in
stocks and that 88% of U.S. adults have investments in fixed income
instruments (savings accounts, bonds, etc.). It is also estimated
that 25% of U.S. adults have investments in both stocks and fixed
income instruments. (a) What is the probability that a randomly
chosen stock investor also invests in fixed income instruments?
Round your answer to 2 decimal places. (b) What is the probability
that a randomly chosen...

In a survey of U.S. adults with a sample size of 2002, 400 said
Franklin Roosevelt was the best president since World War II. Two
U.S. adults are selected at random from the population of all U.S.
adults without replacement. Assuming the sample is representative
of all U.S. adults, complete parts (a) through (d).
(a) Find the probability that both adults say Franklin Roosevelt
was the best president since World War II.
The probability that both adults say Franklin Roosevelt...

a. The number of hours of sleep per night that adults in the
United States is normally distributed with a mean of 6.8 hours and
a standard deviation of 1.4 hours. If the recommended amount of
sleep is 7 hours, what proportion of US adults are getting less
than that amount of sleep? Round to the nearest ten-thousandth.
b. The number of hours of sleep per night that adults in the
United States is normally distributed with a mean of...

The following are the annual incomes (in thousands of dollars)
for 9 randomly chosen, U.S. adults employed full-time: 93, 76, 45,
52, 41, 99, 72, 76, 37
(a) What is the median of this
data set? If your answer is not an integer, round your answer to
one decimal place.
(b) What is the mean of this
data set? If your answer is not an integer, round your answer to
one decimal place.
(c) How many modes
does the data...

ADVERTISEMENT

Get Answers For Free

Most questions answered within 1 hours.

ADVERTISEMENT

asked 1 minute ago

asked 1 minute ago

asked 1 minute ago

asked 1 minute ago

asked 10 minutes ago

asked 14 minutes ago

asked 18 minutes ago

asked 21 minutes ago

asked 28 minutes ago

asked 35 minutes ago

asked 35 minutes ago

asked 36 minutes ago