The following data are required to answer questions 4-7. In Australia, there was a national average of 8 publications per staff member between 1974 and 1996. A random sample of 5 individuals was taken from the 17 members of academic staff at Mudlark University in order to determine whether they were publishing at a rate consistent with the national averages (see data below). An asterisk indicates that the staff member was one of the five sampled individuals.
Staff Member |
Publications |
1* |
7 |
2 |
3 |
3 |
44 |
4 |
4 |
5* |
21 |
6 |
11 |
7 |
10 |
8* |
3 |
9 |
0 |
10 |
6 |
11 |
0 |
12* |
1 |
13 |
2 |
14* |
15 |
15 |
15 |
16 |
0 |
17 |
28 |
4. What is the null hypothesis for this analysis?
5. What is the sample mean?
6. Approximately what is the value of the obtained t-statistic?
7. On the basis of the obtained t-statistic, should you reject the null hypothesis (alpha = .05)?
4. What is the null hypothesis for this analysis?
ans : The sample mean is different from the national average
random sample of 5 staff member
7 |
21 |
3 |
1 |
15 |
mean = 9.4
sd = 8.41
SE = sd/ SQRT(n)
n = 5
5. What is the sample mean?
ans : 9.4
6. Approximately what is the value of the obtained t-statistic?
t - cal | (X_bar - mean ) / SE | 0.372 |
ans : t- stat = 0.37
7. On the basis of the obtained t-statistic, should you reject the null hypothesis (alpha = .05)?
No, the probability is greater than alpha.
becouse of SPSS output t-table value is greater than the t-stat, so accept the null hypothesis.
One-Sample Test |
||||||
Test Value = 8 |
||||||
t |
df |
Sig. (2-tailed) |
Mean Difference |
95% Confidence Interval of the Difference |
||
Lower |
Upper |
|||||
VAR00004 |
.372 |
4 |
.729 |
1.40000 |
-9.0477 |
11.8477 |
Get Answers For Free
Most questions answered within 1 hours.