Question

A mass of 100.00 Kg is weighted using a Digital Balance with 0,01% accuracy. The balance has a 5 digit display with two decimal points. The Expanded Uncertainty as declared in the Certificate of Calibration of the balance is 0,05%. The measurement is repeated 6 times to give 100.0 Kg; 100.1 Kg; 100,0 Kg; 100.1 Kg; 100.2 Kg and 100.2 Kg respectively. Calculate the bias, precision, and the standard error. Calculate the individual standard uncertainties to find the total standard and expanded measurement uncertainties.

Answer 1

Answer:

Here inclination is estimated by the blunder of individual worth, summarize it and gap by watched esteems

inclination = (0 + 0.1 + 0 + 0.1 + 0.2 + 0.2) / 6

= 0.1

so the perceptions are one-sided.

the most noteworthy estimation of observation is 100.2

the most reduced estimation of observation is 100.0

so the accuracy = 100.2 - 100.0

= 0.2

mean = 100.1

deviation is - 0.1, 0, - 0.1,0, 0.1, 0.1

(deviation^2) are 0.001, 0 ,0.001 .0, 0.001 , 0.001

aggregate of (deviation^2) = m = 0.004

m/(n-1) = 0.004/5

= 0.0008

standard deviation = square foundation of (m/(n-1))

= 0.028

standard error= 0.028/sqrt{6}

= 2.45

absolute standard vulnerability is 0.01

absolute consolidated vulnerability = y = 245.2

Hence absolute extended vulnerability = y* inclusion factor