All Canadian high school graduates were assessed on their general knowledge. The results showed an average of 50 and a standard deviation of 14. Suppose that a large number of samples comprising 49 students each are randomly selected and that for each of these samples the average is calculated. What will be the form of distribution of the average samples, the mean of this average sampling distribution and the standard deviation of this average sampling distribution?
Solution :
Given that,
mean = = 50
standard deviation = = 14
n = 49
The distribution of sampling distribution is approximately normal,
= = 50
= / n = 14 / 49 = 2
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