Question

Buy-side vs. sell-side analysts' earnings forecasts. In a study published in Financial Analysts Journal (Jul./Aug. 2008),...

Buy-side vs. sell-side analysts' earnings forecasts.

In a study published in Financial Analysts Journal (Jul./Aug. 2008), 3526 forecasts made by buy-side analysts and 58,562 forecasts made by sell-side analysts were researched. The relative absolute forecast error was determined for each. The mean and standard deviation of forecast errors for both types of analysts are given below.

    Buy-Side Analysts  

Sample Size: 3,526

Mean: 0.85

Standard Deviation: 1.93

Sell-Side Analysts

Sample Size: 58,562

Mean: -0.05

Standard Deviation: 0.85

Construct a 95% confidence interval to estimate the difference in the mean forecast error of buy-side analysts and sell-side analysts.

Note: Define forecast error of buy-side analysts as the first population.

a.) What is the difference in the sample mean forecast error of buy-side analysts and sell-side analysts?

b.) What is the standard error of the difference in mean?

c.) What is the lower bound / lower limit of the 95% confidence interval?

d.) What is the upper bound / upper limit of the 95% confidence interval?

e.) Interpret the confidence interval.

f.) Based on the confidence interval, which type of the analysts has the greater mean forecast error?

Homework Answers

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
A business magazine samples 95 individuals responsible for economic forecasting for regional banks. The population is...
A business magazine samples 95 individuals responsible for economic forecasting for regional banks. The population is large enough that the with/without replacement distinction doesn’t matter. Suppose that the sample of 95 forecasts yields an average prediction of a 3.7% growth in real disposable income. Assume that the population standard deviation is 5%. a) Calculate the lower bound for the 95% confidence interval for the population mean forecast. b) Calculate the upper bound for the 95% confidence interval for the population...
A sample of n = 16 is to be taken from a distribution that can reasonably...
A sample of n = 16 is to be taken from a distribution that can reasonably be assumed to be Normal with a standard deviation σ of 100. The sample mean comes out to be 110. 1. The standard error of the mean, that is, the standard deviation of the sample mean, is σx¯ = σ/√ n. What is its numerical value? 2. The 97.5 percentile, 1.96, of the standard Normal distribution is used for a 95% confi- dence interval....
A simple random sample of size n is drawn from a population that is normally distributed....
A simple random sample of size n is drawn from a population that is normally distributed. The sample mean, x bar over x, is found to be 109, and the sample standard deviation, s, is found to be 10. a) Construct a 96% confidence interval about mu if the sample size, n, is 29 lower bound: __ upper bound: __ b) Re-do, but with a different interval. Construct a 95% confidence interval about mu if sample size n, is 29...
The mean and standard deviation of a random sample of n measurements are equal to 33.9...
The mean and standard deviation of a random sample of n measurements are equal to 33.9 and 3.3, respectively. a. Find the lower limit, the upper limit and the margin of error for a 95% confidence interval for m if n = 100. b. Find the lower limit, the upper limit and the margin of error for  a 95% confidence interval for m if n = 400.
In a random sample of 17 senior-level chemical engineers, the mean annual earnings was 123950 and...
In a random sample of 17 senior-level chemical engineers, the mean annual earnings was 123950 and the standard deviation was 34940. Assume the annual earnings are normally distributed and construct a 95% confidence interval for the population mean annual earnings for senior-level chemical engineers. 1. The critical value: 2. The standard error of the sample mean: 3. The margin of error: 4. The lower limit of the interval: 5. The upper limit of the interval:
In a random sample of 15 senior-level chemical engineers, the mean annual earnings was 122050 and...
In a random sample of 15 senior-level chemical engineers, the mean annual earnings was 122050 and the standard deviation was 34680. Assume the annual earnings are normally distributed and construct a 95% confidence interval for the population mean annual earnings for senior-level chemical engineers. 1. The critical value: 2. The standard error of the sample mean: 3. The margin of error: 4. The lower limit of the interval: 5. The upper limit of the interval:
In a random sample of 14 senior-level chemical engineers, the mean annual earnings was 138850 and...
In a random sample of 14 senior-level chemical engineers, the mean annual earnings was 138850 and the standard deviation was 35800. Assume the annual earnings are normally distributed and construct a 95% confidence interval for the population mean annual earnings for senior-level chemical engineers. 1. The critical value: 2. The standard error of the sample mean: 3. The margin of error: 4. The lower limit of the interval: 5. The upper limit of the interval:
In a random sample of 19 senior-level chemical engineers, the mean annual earnings was 132150 and...
In a random sample of 19 senior-level chemical engineers, the mean annual earnings was 132150 and the standard deviation was 35660. Assume the annual earnings are normally distributed and construct a 95% confidence interval for the population mean annual earnings for senior-level chemical engineers. 1. What is the critical value? 2. What is the standard error of the sample mean? 3. The margin of error? 4. The lower limit of the interval? 5. The upper limit of the interval?
A simple random sample of size n is drawn from a population that is normally distributed....
A simple random sample of size n is drawn from a population that is normally distributed. The sample mean x bar is found to be 109, and the sample standard​ deviation, s, is found to be 10. a. Construct 95% confidence interval about miu, if the sample size n is 28. Find lower and upper bound. ​b. Construct 95% confidence interval about miu, if the sample size n is 17. Find lower and upper bound. c.Construct 80% confidence interval about...
1)Given a sample mean is82, the sample size is 100and the population standard deviation is 20....
1)Given a sample mean is82, the sample size is 100and the population standard deviation is 20. Calculate the margin of error to 2 decimalsfor a 90% confidence level. 2)Given a sample mean is 82, the sample size is 100 and the population standard deviation is 20. Calculate the confidence interval for 90% confidence level. What is the lower limit value to 2 decimals? 3)Given a sample mean is 82, the sample size is 100 and the population standard deviation is...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT