Question

A diet doctor claims that the average North American is more than 20 pounds overweight. To...

A diet doctor claims that the average North American is more than 20 pounds overweight. To test his claim, a random sample of 20 North Americans was weighed, and the difference between their actual and ideal weights was calculated. The data is listed below: 16 23 18 41 22 18 23 19 22 15 18 35 16 15 17 19 23 15 16 26 The sample statistics are: ?̅ = 20.85, ? = 6.76. Can we infer, at the 5% significance level, that the doctor’s claim is true? How would you solve this using excel?

Math   Statistics-And-Probability   
0 0
Add a commentTranscribed image text
Next >

Homework Answers

Answer #1

0 0
Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
A diet doctor claims that the average North American is more than 20 pounds overweight. To...
A diet doctor claims that the average North American is more than 20 pounds overweight. To test his claim, a random sample of 20 North Americans was weighed, and the difference between their actual and ideal weights was calculated. The data is listed below: 16 23 18 41 22 18 23 19 22 15 18 35 16 15 17 19 23 15 16 26 The sample statistics are: ?̅= 20.85, ? = 6.76. Can we infer, at the 5% significance...
A diet doctor claims that the average North American is more than 20 pounds overweight. To...
A diet doctor claims that the average North American is more than 20 pounds overweight. To test his claim, a random sample of 30 North Americans was weighted, and the difference between their actual weight and their ideal weight was calculated. The sample mean is 20.85 pounds and the sample standard deviation is 3.76 pounds. Find the p-value for this hypothesis test. H_{a} \:: \mu >20 H a : μ > 20 pounds
A nutrition expert claims that the average American is overweight. To test his claim, a random...
A nutrition expert claims that the average American is overweight. To test his claim, a random sample of 22 Americans was selected, and the difference between each person's actual weight and idea weight was calculated. For this data, we have x¯=18.2x¯=18.2 and s=29.4s=29.4. Is there sufficient evidence to conclude that the expert's claim is true? Carry out a hypothesis test at a 4% significance level. A. The value of the standardized test statistic: Note: For the next part, your answer...
A doctor discovers a particular disease and determines the life expectancy is not good. He gathers...
A doctor discovers a particular disease and determines the life expectancy is not good. He gathers the data for his patents and posts it in the table below. The claims that the average life expectancy once the disease presents itself is less than 15 days. Check his claim and make an appropriate report about your findings Patient Days till passing 1 24 2 23 3 13 4 20 5 10 6 18 7 13 8 14 9 24 10 25...
We want to compare the average gas mileage of American-made cars vs. Japanese-made cars. The claim...
We want to compare the average gas mileage of American-made cars vs. Japanese-made cars. The claim is that the Japanese cars and American cars do not get the same gas mileage. Use the list data below to test the hypothesis that the Japanese cars and American cars do not get the same gas mileage. The American cars are in list1 and the Japanese cars in list2 below We do not know whether the mileages are normally distributed or not, but...
a sample have 10 students the average score in math is less than the average in...
a sample have 10 students the average score in math is less than the average in english x1= test scores in math x2= test scores in english assume the scores follow normal distribution let u1 be the population mean of math scored let u2 be the population mean of english score the score are given below student. math. english 1. 18. 22 2. 22. 24 3. 19. 16 4. 23. 19 5. 20. 21 6. 18. 18 7. 16. 17...
Is there an association between patient BMI and cholesterol level at screening? Consider overweight, normal and...
Is there an association between patient BMI and cholesterol level at screening? Consider overweight, normal and underweight categories for BMI. Do a Chi-Square. I am having trouble finding the test statistics. I picked the level of significance to be 5%. Patient ID Drug Sex Age Height BMI Weight Cholesterol 1 B F 22 67.13 21.52787 138 197 2 B M 22 63 20.36911 115 181 3 B F 22 72 25.76582 190 190 4 A M 22 69 16.98068 115...
A shoe manufacturer claims that among the general population of adults in the United States, the...
A shoe manufacturer claims that among the general population of adults in the United States, the average length of the left foot is longer than that of the right. A random (okay, this is reaching a little bit but I wanted to use our data) sample of 23 adults is listed below. Sample Left (inches) Right (inches) 1 9.25 9.25 2 9.125 9.25 3 10.2 10.2 4 10.25 10.25 5 9.875 9.75 6 8.25 8.5 7 9.1 8.9 8 8.2...
What is the probability of finding a sample with a mean of less than 29,000 miles?...
What is the probability of finding a sample with a mean of less than 29,000 miles? Tire # Mileage 1 30564 2 28886 3 29822 4 29326 5 31535 6 31880 7 28376 8 29664 9 25001 10 31981 11 31048 12 29672 13 33267 14 31512 15 35228 16 27089 17 31372 18 32749 19 28670 20 31683 21 34551 22 31811 23 29535 24 25741 25 28874 26 28535 27 28444 28 27504 29 32179 30 31491 31...
Is there enough evidence that the average number of PURPLE Skittles in a package is greater...
Is there enough evidence that the average number of PURPLE Skittles in a package is greater than the average number of ORANGE Skittles in a package? Use the attached Skittles sample and test at the significance level of .01 Package Red Orange Yellow Green Purple Total Dominant Color 1 15 15 16 12 14 72 Y 2 13 6 11 16 15 61 G 3 9 9 10 18 15 61 G 4 7 9 8 18 15 57 G...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT