Question

2. Before completing this question, review Chapter 15 of your SPSS textbook and complete the example in the chapter (the example starts at the beginning of the chapter) to learn how to conduct One-Way ANOVA.

Researchers recorded the weights in pounds of sixteen study participants residing in four different cities across the United States. The results of the study are presented in Table 3.The objective for this study was to identify the differences in weight of study participants residing in the four different cities.

Your task for this assignment is to analyze the data in Table 3 and conduct hypothesis testing.

To complete this exercise, you must follow the steps of hypothesis testing (see Hypothesis Testing (PDF)). Make sure that in your Word document you demonstrate you followed each of the steps! Feel free to refer to your assignment for Module 4 if you need guiding questions to help you complete this part of the assignment.

Table 3.

Weight in pounds (lbs) of 20 study participants living in four different cities in the United States

Cities*	Weight in lbs.
Roanoke (1)	160
Roanoke (1)	120
Roanoke (1)	121
Roanoke (1)	126
Roanoke (1)	159
Marietta (2)	122
Marietta (2)	138
Marietta (2)	151
Marietta (2)	156
Marietta (2)	140
Elk City (3)	133
Elk City (3)	149
Elk City (3)	150
Elk City (3)	129
Elk City (3)	144
Gallup (4)	178
Gallup (4)	143
Gallup (4)	135
Gallup (4)	135
Gallup (4)	133

*Use the numbers in parenthesis to code the variable in SPSS

Answer 1

Roanoke (1)	Marietta (2)	Elk City (3)	Gallup (4)
160	122	133	178
120	138	149	143
121	151	150	135
126	156	129	135
159	140	144	133

Anova: Single Factor
SUMMARY
Groups	Count	Sum	Average	Variance
Roanoke (1)	5	686	137.2	419.7
Marietta (2)	5	707	141.4	173.8
Elk City (3)	5	705	141	90.5
Gallup (4)	5	724	144.8	359.2
ANOVA
Source of Variation	SS	df	MS	F	P-value	F crit
Between Groups	145	3	48.33333	0.185327	0.904816	3.238872
Within Groups	4172.8	16	260.8
Total	4317.8	19

Here

MS = SS/df

F ratio = MS (Between Group) / MS (within group)

Ho = Means is different

Ha = Mean is same

F ratio is 0.18 is less than F critical 3.22

i.e We reject null hypothesis and accept alternate hypotheis

Mean of different groups is same